问题标题:
分解因式:(x-2)2-(y-2)2-(x-y)2.
更新时间:2024-04-27 15:52:14
问题描述:
分解因式:(x-2)2-(y-2)2-(x-y)2.
李晔回答:
原式=[(x-2)+(y-2)][(x-2)-(y-2)]-(x-y)2
=[x+y-4][x-y]-(x-y)2
=(x-y)[(x+y-4)-(x-y)]
=(x-y)(2y-4)
=2(x-y)(x-2).
分解因式:(x-2)2-(y-2)2-(x-y)2.